32-28b-15b^2=0

Solution for 32-28b-15b^2=0 equation:

32-28b-15b^2=0

a = -15; b = -28; c = +32;
Δ = b2-4ac
Δ = -282-4·(-15)·32
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-52}{2*-15}=\frac{-24}{-30}
=4/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+52}{2*-15}=\frac{80}{-30}
=-2+2/3
$